Introduction into the
Symmetry of Molecules

Step: 141

Preface (german) Table of Content Remarks Imprint

2. There are no S ₈ = C _4, also perpendicularly to it a standing C ₂ is missing, likewise no s _h but several s _v
Thus is the group of points of [ CrCl ₅(H ₂O) ] ^2- is C _4v
If you came to another result, go through the example again thoroughly and find your error.

Continue please the course with training step 142

Introduction into the Symmetry of Molecules

Step: 141

Introduction into the
Symmetry of Molecules